Question 578001: You are hired to monitor quality control for a clothes manufacture. The manufacture claims that only 5% of jeans manufactured have a defect.
A.) using the manufactures claim, write P(no defect) and P(defect) as decimals.
B.) at a checkpoint, you choose six pairs of jeans at random and determine that two pairs have a defect. Find the probability of this happening by chance, using the probabilities you wrote in part a.
C.) using your results from part b, do you believe the manufactures claim about quality control? Explain
Answer by dfrazzetto(283)   (Show Source):
You can put this solution on YOUR website! A) P(no defect) = 100% - 5% = 95% = .95
P(defect) = 5% = .05
B) 2 defective / 6 total = 33% = .33 which is much higher than the probability by chance asserted by the manufacturer
C) .33 is much larger than .05, so it would be hard to believe the manufacturers claim, but our sample size n=6 was very small, to get more accurate representation, would have been better to include a larger sample size, of at least n=20
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