Question 577912: In the game of blackjack as played in casinos in Las Vegas, Atlantic City, Niagara Falls, as well as many other cities, the dealer has the advantage. Most players do not play very well. As a result, the probability that the average player wins a hand is about 0.46. Find the probability that an average player wins
A. twice in 5 hands.
B. 10 or more times in 26 hands.
There are several books that teach blackjack players the "basic strategy" which increases the probability of winning any hand to 0.53. Assuming that the player plays the basic strategy, find the probability that he or she wins
C. twice in 5 hands.
D. 10 or more times in 26 hands.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In the game of blackjack as played in casinos in Las Vegas, Atlantic City, Niagara Falls, as well as many other cities, the dealer has the advantage. Most players do not play very well. As a result, the probability that the average player wins a hand is about 0.46. Find the probability that an average player wins
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Binomial Problem with p = 0.46
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A. twice in 5 hands.
P(x = 2) = 5C2*0.46^2*0.54^3 = binompdf(5,0.46,2) = 0.3332
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B. 10 or more times in 26 hands.
P(10<= x <=26) = 1 - P(0<= x <=9) = 1 - binomcdf(26,0.46,9) = 0.8333
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Use the same procedure as above to answer the following questions:
There are several books that teach blackjack players the "basic strategy" which increases the probability of winning any hand to 0.53. Assuming that the player plays the basic strategy, find the probability that he or she wins
C. twice in 5 hands.
D. 10 or more times in 26 hands.
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Cheers,
Stan H.
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