SOLUTION: Can you teach me how to solve this problem.
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the secon
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-> SOLUTION: Can you teach me how to solve this problem.
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the secon
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Question 57787: Can you teach me how to solve this problem.
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers.
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Notice that the 1st and the 3rd are described in terms of the 2nd.
So. let the 2nd number be "x".
Then the 3rd is "10x-11"
Since 2(1st)=3x+7, 1st is (1/2)(3x+7)
EQUATION:
1st + 2nd + 3rd = 105
(1/2)(3x+7)+x+10x-11=105
(3/2)x+(7/2)+11x-11=105
(25/2)x=112.50
25x=225
x=9 (this is the 2nd number)
3rd number is 10x-11=79
1st number is (1/2)(3*9+7)=17
Cheers,
stan H.
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