SOLUTION: how many liters of a 50% acid solution must be mixed with a 30% acid solution to get 200 L of a 40% acid solution?

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Question 577678: how many liters of a 50% acid solution must be mixed with a 30% acid solution to get 200 L of a 40% acid solution?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
percent ---------------- quantity
Acod solution type I 50.00% ---------------- x liters
Acid solution type II 30.00% ------ 200 - x liters
Mixture 40.00% ---------------- 200

50.00% x+30.00%(200-x)=40.00% * 200
50x+30(200-x)= 8000
50x+6000-30x=8000
50x-30x =8000-6000
20x= 2000
/ 20
x= 100 liters 50.00% Acid solution type I
100 liters 30.00% Acid solution type II 50
m.ananth@hotmail.ca