Question 577465: Factor b(b-2)(b+1)- 3 - 3b
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Factor
b(b-2)(b+1)- 3 - 3b
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b(b-2)(b+1)-3(1+b)
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Common factor: (b+1)
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Factoring you get:
(b+1)[b(b-2)-3]
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= (b+1)(b^2-2b-3)
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= (b+1)(b-3)(b+1)
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= (b+1)^2*(b-3)
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Cheers,
Stan H.
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