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Question 576785: eight times the larger of two numbers decreased by three times the smaller is 148. nine times the smaller decreased by twenty is equal to eight times the larger. find the two numbers
Answer by chana(69)   (Show Source):
You can put this solution on YOUR website! eight times the larger of two numbers decreased by three times the smaller is 148. nine times the smaller decreased by twenty is equal to eight times the larger. find the two numbers
sol :
forming the equation with the given datas :
let x be the larger number and y be the smaller number
so as given 8x - 3y = 148 ------(1)
9y - 20 = 8x ----------(2)
solve the anove two equation for x & y ,you will get the required nos ,where x = 29 , y = 28.
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