SOLUTION: Consider a binomial random variable where the number of trials is 9 and the probability of success on each trial is 0.43. Find the mean and standard deviation of this random vari

Algebra ->  Probability-and-statistics -> SOLUTION: Consider a binomial random variable where the number of trials is 9 and the probability of success on each trial is 0.43. Find the mean and standard deviation of this random vari      Log On


   

Question 576566: Consider a binomial random variable where the number of trials is 9 and the probability of success on each trial is 0.43. Find the mean and standard deviation of this random variable.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
mean = np = 9*0.43 = 3.87

standard deviation = sqrt(np(1-p)) = sqrt(9*0.43*(1-0.43)) = 1.485227