SOLUTION: Find the minimum of P(x) = 3x^2 + 6x - 1.

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Question 57595This question is from textbook Applied College Algebra
: Find the minimum of P(x) = 3x^2 + 6x - 1. This question is from textbook Applied College Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the minimum of P(x) = 3x^2 + 6x - 1.
Minimum is at x=-b/2a=-6/6=-1
P(-1)=3-6-1=-4
Minimum at (-1,-4)
Cheers,
Stan H.