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| Question 57581:  t^2+1=13/6t
 Answer by terbear1963(43)
      (Show Source): 
You can put this solution on YOUR website! FIRST MULTIPLY EACH SIDE BY 6 TO GET RID OF YOUR MENACING FRACTIONS!!!                 6(T^2+1)=(13/6T)6 ---> 6T^2+6=13T --->            6T^2-13T+6=0 ---> (3T-2)(2T-3)=0 ---> 3T-2=0 AND 2T-3=0  ---> T=2/3 AND T=3/2 I HOPE THIS HELPS YOU!? YOUR MATH FRIEND , TERRY ( CATS7051@YAHOO.COM )
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