SOLUTION: w^3+5w^2-w=5 can someone please help. thank you in advance

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: w^3+5w^2-w=5 can someone please help. thank you in advance      Log On


   



Question 57580: w^3+5w^2-w=5
can someone please help. thank you in advance

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
w%5E3%2B5w%5E2-w=5 Set = to 0
w%5E3%2B5w%5E2-w-5=5-5
w%5E3%2B5w%5E2-w-5=0 Factor by grouping
%28w%5E3%2B5w%5E2%29%2B%28-w-5%29=0 Factor the GCF in each group
w%5E2%28w%2B5%29-1%28w%2B5%29=0 Factor out w+5
%28w%2B5%29%28w%5E2-1%29=0 Factor w%5E2-1, it's the difference of squares
%28w%2B5%29%28w%2B1%29%28w-1%29=0 Set each parenthesis = 0 and solve for w.
w+5=0 and w+1=0 and w-1=0
w+5-5=0-5 and w+1-1=0-1 and w-1+1=0+1
w=-5 and w=-1 and w=1
Some books write the solution set as: w={-5,-1,1}
Happy Calculating!!!