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Question 575138: Mary has two tanks of fish. If she transfers 15 fish from the larger tank to the smaller tank, then the number of fish in the smaller tank will be 5/7 of the number of fish in the larger tank. Given that there are 35 fish in the smaller tank originally, find the number of fish in the larger tank before the transfer of fish.
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This is what I tried:
=5/7 - 35/1= -310/7
=310÷7= 44.2....
=59 fish
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Answer by chana(69)   (Show Source):
You can put this solution on YOUR website! Mary has two tanks of fish. If she transfers 15 fish from the larger tank to the smaller tank, then the number of fish in the smaller tank will be 5/7 of the number of fish in the larger tank. Given that there are 35 fish in the smaller tank originally, find the number of fish in the larger tank before the transfer of fish.
sol:
let the no of fish in larg tank = L
no of fishes in the small tank = S
originally S = 35
after transfer S = 35+ 15 = 50.
after transfer 5/7 * L = 50
so L after tranfer = 70
which gives before transfer = 70 + 15 = 85
fish in the large tank originally = 85
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