SOLUTION: I want to know if this problem is correct: (y-2/3)^2 = 49 y - 2/3 = + or - Square root 2/3 If y - 2/3 = 2/3 then y = 4/3 If y - 2/3 = -2/3 then y = 0 Is this solutio

Algebra ->  Radicals -> SOLUTION: I want to know if this problem is correct: (y-2/3)^2 = 49 y - 2/3 = + or - Square root 2/3 If y - 2/3 = 2/3 then y = 4/3 If y - 2/3 = -2/3 then y = 0 Is this solutio      Log On


   



Question 57477: I want to know if this problem is correct:
(y-2/3)^2 = 49
y - 2/3 = + or - Square root 2/3
If y - 2/3 = 2/3 then y = 4/3
If y - 2/3 = -2/3 then y = 0
Is this solution correct the way it is worked out?

Answer by rcmcc(152) About Me  (Show Source):
You can put this solution on YOUR website!
Solving for y (y-2/3)^2 = 49

because the square sign is on the entire left term, it can be removed by square routing the right term. because the negative of the square rout is extraneous, it does not have to be counted.
(y-2/3)^2 = 49
y-(2/3)=7
now you add (2/3) to isolate y
y=7(2/3)
(*remember bracket rules)