SOLUTION: Andrew made a deposit of 10, 600 pesos. If his deposit consisted of 42 bills, some 100 peso bills and the rest are 500 peso bills, how many bills of each kind did he have?
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Question 574744: Andrew made a deposit of 10, 600 pesos. If his deposit consisted of 42 bills, some 100 peso bills and the rest are 500 peso bills, how many bills of each kind did he have? Answer by ad_alta(240) (Show Source):
You can put this solution on YOUR website! Let 'H' be the number of hundred peso bills and 'F' the number of five hundred peso bills. We know H+F=42 and 100*H+500*F=10600. Substituting the first equation into the second we get 100*(42-F)+500*F=10600. We get F=16 and H=26.
