SOLUTION: If 3x^2-2x+7=0, then (x-1/3)^2 = ?
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Question 574596
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If 3x^2-2x+7=0, then (x-1/3)^2 = ?
Answer by
jim_thompson5910(35256)
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3x^2-2x+7=0
3x^2-2x=-7
3(x^2-2/3x)=-7
3(x^2-2/3x+1/9)=-7+3*(1/9)
3(x^2-2/3x+1/9) = -20/3
3(x-1/3)^2 = -20/3
(x-1/3)^2 = (-20/3)/3
(x-1/3)^2 = -20/9