SOLUTION: 1)1. Solve the equation 3(2x-1) + x = 5x+3. a. 0 b. 3 c. 3/2 d. no solution 2)2. Use the quadratic formula to solve y2+10y+24 = 0. 3)3. Solve by factoring: a2 -5a-14 = 0. a.

Algebra ->  Trigonometry-basics -> SOLUTION: 1)1. Solve the equation 3(2x-1) + x = 5x+3. a. 0 b. 3 c. 3/2 d. no solution 2)2. Use the quadratic formula to solve y2+10y+24 = 0. 3)3. Solve by factoring: a2 -5a-14 = 0. a.      Log On


   



Question 57442: 1)1. Solve the equation 3(2x-1) + x = 5x+3.
a. 0
b. 3
c. 3/2
d. no solution
2)2. Use the quadratic formula to solve y2+10y+24 = 0.
3)3. Solve by factoring: a2 -5a-14 = 0.
a. 5, 14
b. -7, 2
c. 2, 7
d. 7, -2
4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.
a. (- ∞ , 4]
b. [4, ∞ )
c. (- ∞ , 2/3]
d. [2/3, ∞ )

Found 2 solutions by funmath, Nate:
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
1)1. Solve the equation 3(2x-1) + x = 5x+3.
highlight%28a%29. 0
b. 3
c. 3/2
d. no solution
3(2x-1)+x=5x+3
6x-3+x=5x+3
7x-3=5x+3
-5x+7x+3=-5x+5x+3
2x+3=3
2x+3-3=3-3
2x=0
2x/2=0/2
x=0 (a)
:
2)2. Use the quadratic formula to solve y%5E2%2B10y%2B24=0.
a=1, b=10,c=24
The quadratic formula is:
highlight%28x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29%29
x=%28-%2810%29%2B-sqrt%28%2810%29%5E2-4%281%29%2824%29%29%29%2F%282%281%29%29
x=%28-10%2B-sqrt%28100-96%29%29%2F%282%281%29%29
x=%28-10%2B-sqrt%284%29%29%2F2
x=%28-10-sqrt%284%29%29%2F2 and x=%28-10%2Bsqrt%284%29%29%2F2
x=%28-10-2%29%2F2 and x=%28-10%2B2%29%2F2
x=-12%2F2 and x=-8%2F2
x=-6 and x=-4
:
3)3. Solve by factoring: a%5E2-5a-14+=+0.
a. 5, 14
b. -7, 2
c. 2, 7
highlight%28d%29. 7, -2
a%5E2-5a-14=0 Two numbers that multiply to get -14, but add to get -5 are -7 and 2. -7*2=-14 and -7+2=-5
%28a-7%29%28a%2B2%29=0
a-7=0 and a%2B2=0
a=7 and a=-2
:
4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.
a. (- infinity; , 4]
b. [4, infinity )
highlight%28c%29. (-infinity, 2/3]
d. [2/3, infinity )
3x%2B5%3C=7
3x%2B5-5%3C=7-5
3x%3C=2
3x%2F3%3C=2%2F3
x%3C=2%2F3
(-infinity,2/3]
Happy Calculating!!!

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
1)1. Solve the equation 3(2x-1) + x = 5x + 3.
6x - 3 + x = 5x + 3
7x - 3 = 5x + 3
2x = 6
x = 3
b.
2)2. Use the quadratic formula to solve y2+10y+24 = 0.
x+=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-10+%2B-+sqrt%28+100+-+96+%29%29%2F%282%29+
x+=+%28-10+%2B-+2%29%2F%282%29+
x+=+-6 and x+=+-4
3)3. Solve by factoring: a2 - 5a - 14 = 0.
(x - 7)(x + 2) = 0
x = 7 and x = -2
d.
4)4. Solve the inequality 3x + 5< with - under < 7 . Write the solution using interval notation.
3x+%2B+5+%3C=+7
3x+%3C=+2
x+%3C=+2%2F3
(-inf,2/3]
c.