SOLUTION: I have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line. Point: (-9,8) Line: x+y=15 Then I have to write t

Algebra ->  Linear-equations -> SOLUTION: I have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line. Point: (-9,8) Line: x+y=15 Then I have to write t      Log On


   



Question 574378: I have to write the slope-intercept form of the equation of the line through the given point and parallel to the given line.
Point: (-9,8) Line: x+y=15
Then I have to write the slope-intercept form of the equation of the line through the given point and perpendiulat to the given line.
HELP!

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
parallel means the x and y coefficients are the same, just substitute in the point to find the new constant term

(-9) + (8) = -1 ___ so the new equation is, x + y = -1
___ get the y by itself for slope-intercept ___ y = -x - 1


perpendicular means the slopes are negative reciprocals, so the slope changes from -1 to 1 ___ y = x + b

to find the b term, substitute in the point (again)
___ (8) = (-9) + b ___ 17 = b

so the perpendicular equation is ___ y = x + 17