SOLUTION: Prove that:~ cotB + tanB = cotB sec^2B
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Question 574298
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Prove that:~
cotB + tanB = cotB sec^2B
Answer by
Alan3354(69443)
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Prove that:~
cotB + tanB = cotB sec^2B
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Multiply thru by tan(B)
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1 + tan^2 = sec^2
I'm convinced
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If you're not, multiply thru by cos^2
cos^2 + sin^2 = 1