Question 574248: solve x in 6(x^+1)=13x
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! You have a typo in your expression. I'm going to assume it's a quadratic:
solve x in 6(x^2+1)=13x
.
To solve any quadratic, set one side to zero:
6(x^2+1)=13x
6x^2+6=13x
6x^2-13x+6=0
6x^2-9x-4x+6=0
group:
(6x^2-9x)-(4x-6)=0
3x(2x-3)-2(2x-3)=0
(2x-3)(3x-2) = 0
x = {3/2, 2/3}
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