SOLUTION: a collection of dimes and quarters is worth $16.20. there are 81 coins in all. how many dimes and how many quarters?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: a collection of dimes and quarters is worth $16.20. there are 81 coins in all. how many dimes and how many quarters?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 574161: a collection of dimes and quarters is worth $16.20. there are 81 coins in all. how many dimes and how many quarters?
Answer by Maths68(1474) About Me  (Show Source):
You can put this solution on YOUR website!

Let
Quarters=x
Dimes=81-x
Total Coins=81
Value of a Quarter = $0.25
Value of a Dime = $0.10
Total value of all coins = $16.20

(Value of a Quarter)(Quarters)+(Value of a Dimes)(Dimes)= Total value of all coins
(0.25)(x)+(0.10)(81-x)=16.20
0.25x+8.1-0.10x=16.20
0.25x-0.10x=16.20-8.10
0.15x=8.1
0.15x/0.15=8.1/0.15
x=54


Quarters=x=54
Dimes=81-x=81-54=27


Check
=====
Total Quarters*value of a Quarter+Total Dimes*value of a Dime = Total Amount
54*0.25+27*0.1=16.20
13.5+2.7=16.20
16.20=16.20