Question 573945: The pressure of a gas varies jointly as the amount of the gas(measured in moles) and the temperature and inversely as the volume of the gas. If the pressure is 1125(kPa) when the number of moles is 4, the temperature is 250K and the volume is 480cc, find the pressure when the number of moles is 2, the temperature is 290K, and the volume is 120cc. For the formula I'm trying
1125=k(4)(250)/480. and k=540,000. That can't be right.HELP!
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The pressure of a gas varies jointly as the amount of the gas(measured in moles) and the temperature and inversely as the volume of the gas. If the pressure is 1125(kPa) when the number of moles is 4, the temperature is 250K and the volume is 480cc, find the pressure when the number of moles is 2, the temperature is 290K, and the volume is 120cc.
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P*V = nRT
1125*480 = 4R*250
R = 540000/1000 = 540
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PV = 2*540*290
P = 313200 KPa
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