You can put this solution on YOUR website! Factoring Trinomials by Trial and Error
20x^2+29x+5
The possible factors of 20x^2 are:
20x*x, 2x*10x, 4x*5x,
These are the possible first term of each parntheis.
:
The possible facotrs of 5 are:
1*5, and 5*1
:
Let's start the trial:
(20x+1)(x+5)=20x^2+100x+x+5=20x^2+101x+5 ERROR
(20x+5)(x+1)=20x^2+20x+5x+5=20x^2+25x+5 ERROR
(2x+1)(10x+5)=20x^2+10x+10x+5=20x^2+20x+5 ERROR
(2x+5)(10x+1)=20x^2+2x+50x+5=20x^2+52x+5 ERROR
(4x+1)(5x+5)=20x^2+20x+5x+5=20x^2+25x+5 ERROR
(4x+5)(5x+1)=20x^2+4x+25x+5=20x^2+29x+5 Correct, this is it!!!
If you practice enough, you'll know which numbers to try. There are more methodical methods to use.
Happy Calculating!!!