SOLUTION: Find three consecutive even integers such that the product of the two smaller exceeds the largest by 38

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Find three consecutive even integers such that the product of the two smaller exceeds the largest by 38      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 573926: Find three consecutive even integers such that the product of the two smaller exceeds the largest by 38
Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the smallest of the three integers. The next larger even integer is then and the one after that is .





Solve for . Discard the odd root. Then calculate and

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Call the smallest even integer +n+
The 3 consecutive even integers are
+n+, +n+%2B+2+, and +n+%2B+4+
given:
+n%2A%28+n+%2B+2+%29+=+n+%2B+4+%2B+38+
----------------------
+n%5E2+%2B+2n+=+n+%2B+42+
+n%5E2+%2B+n+-+42+=+0+
Using the quadratic formula,
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
+a+=+1+
+b+=+1+
+c+=+-42+
Solve for n, then find +n%2B+2+ and
+n%2B+4+
I have to run, sorry