|
Question 573848: use the information provided to write the vertex form equation of each parabola.
vertex(-6,9) focus (-6,109/12)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! use the information provided to write the vertex form equation of each parabola.
vertex(-6,9) focus (-6,109/12)
**
Standard form of equation for parabola opening upwards:
(x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the center.
For given parabola:
vertex: (-6,9) (given)
axis of symmetry:x=-6
p=(109/12)-9=(109/12)-(108/12)=1/12 (distance from vertex to focus on the axis of symmetry)
4p=4/12=1/3
equation:
(x+6)^2=(1/3)(y-9)
|
|
|
| |
