SOLUTION: Soybean meal is 14%. cornmeal is 7% protien. How many pounds of eachshouldbe mixed together in order to get 280lb mixture that is 12% protien

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Question 573810: Soybean meal is 14%. cornmeal is 7% protien. How many pounds of eachshouldbe mixed together in order to get 280lb mixture that is 12% protien
Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=amount of soybean meal needed
Then 280-x=amount of cornmeal needed
Now we know that the amount of pure protein that exists before the mixture takes place has to equal the amount of pure protein that exists after the mixture takes place, sooooo:
0.14x+0.07(280-x)=0.12*280
0.14x+19.6-0.07x=33.6
0.07x=33.6-19.6
0.07x=14
x=200 lb----amount of soybean meal needed
280-x=280-200=80 lb ----amount of cornmeal needed
CK
200*0.14+0.07*80=0.12*280
28+5.6=33.6
33.6=33.6

Hope this helps----ptaylor