SOLUTION: Find a number such that twice the number increased by seven is the same as four times the number decreased by three.

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Question 573803: Find a number such that twice the number increased by seven is the same as four times the number decreased by three.
Answer by mathsmiles(68) About Me  (Show Source):
You can put this solution on YOUR website!
Let's let X be the number we're looking for.

The problem says if we take twice the number increased by 7 or ...
2X + 7
it should equal four times the number decreased by 3 ...
4X - 3

Let's find it!

2X + 7 = 4X - 3
Subtract 2X from each side:
7 = 2X - 3
Add 3 to each side:
10 = 2X
Divide both sides by 2
5 = X

Checking:
2(5) + 7 = 4(5) - 3?
10 + 7 = 20 - 3?
17 = 17 Correct!