SOLUTION: A mother jogs at the same rate of 4.5 mph and her daughter jogs at the rate of 5 mph. The mother begins her jog and, 15 minutes later, the daughter begins her jog following the sa
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Question 573483: A mother jogs at the same rate of 4.5 mph and her daughter jogs at the rate of 5 mph. The mother begins her jog and, 15 minutes later, the daughter begins her jog following the same route. How long will it take the daughter to overtake her mother and how far will they have jogged? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! The Mother's head start is: hrs ( or 1 hr 7.5 min )
Now start a stopwatch when Daughter leaves
They will jog for the same amount of time, , until they meet
Let the distance Daughter jogs until they meet =
Daughter's equation:
(1)
Mother's equation:
(2)
Substitute (1) into (2)
(2)
(2)
(2)
(2)
It will take the Daughter 2 hrs and 15 min to catch her Mother
and, since
(1)
(1)
(1) mi
They both will have jogged 11.25 mi
check answer:
(2)
(2)
(2)
OK
