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| Question 572991:  A mother is 3 times as old as her daughter. Seven years ago, she was 5 times as old. How old are the mother and daughter now?
 Answer by mathsmiles(68)
      (Show Source): 
You can put this solution on YOUR website! Let's let M = mother's age now.
 D = daughter's age now.
 
 M = 3 x D
 
 Seven years ago, mother was M-7 years old; daughter was D-7 years old
 At that time, mother was 5 times daughter's age.
 
 M-7 = 5(D-7)
 
 Substituting from the previous equation for mother's age:
 (3D)-7 = 5(D-7)  Multiplying out to remove the parens:
 3D - 7 = 5D - 35
 Subtract 3D from both sides of the equation:
 -7 = 2D -35
 Add 35 to both sides of the equation:
 28 = 2D
 Divide both sides by 2
 14 = D
 
 Daughter is 14, mother is 3 times her age, so 14x3 = 42
 
 Checking:
 Seven years ago, daughter was 7, mother was 35.  Mother was 5 times as old as daughter.  Correct!
 
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