SOLUTION: We can't seem to understand the method for putting together the equation on a Mixture Word Problem. The MATH is no problem; only the organization of the equation itself: Two ki

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Question 572988: We can't seem to understand the method for putting together the equation on a Mixture Word Problem. The MATH is no problem; only the organization of the equation itself:
Two kinds of coffee were blended together, one worth $6.50 a pound and the other worth $5.95 a pound. The blend contained ten pounds more than twice as much as the $5.95 coffee than of the $6.50 coffee. How much of each kind was used if the value of the blend is $280.30?
Found 2 solutions by nerdybill, mananth:
Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
Two kinds of coffee were blended together, one worth $6.50 a pound and the other worth $5.95 a pound. The blend contained ten pounds more than twice as much as the $5.95 coffee than of the $6.50 coffee. How much of each kind was used if the value of the blend is $280.30?
.
Let x = amount (lbs) of $5.95 coffee
then
2x+10 = amount (lbs) of $6.50 coffee
.
5.95x + 6.50(2x+10) = 280.30
5.95x + 13x+65 = 280.30
18.95x+65 = 280.30
18.95x = 215.3
x = 11.36 lbs ($5.95 coffee)
.
$6.50 coffee:
2x+10 = 2(11.36)+10 = 32.72 lbs

Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
Coffee type A $6.50 -----------x pounds
Coffee type B $5.95-------------y pounds
y=2x+10
6.50x+5.95y=280.30
multiply by 100
650x+595y=28030

-2 x + 1 y = 10 .............1
650 x + 595 y = 28030 .............2
Eliminate y
multiply (1)by 595
Multiply (2) by -1
-1190 x 595 y = 5950
-650 x + -595 y = -28030
Add the two equations
-1840 x = -22080.00
/ -1840
x = 12
plug value of x in (1)
-2 x + 1 y = 10
-24 + 1 y = 10
1 y = 34 -27
1 y = 34
y = 34
12 pounds coffee type A
34 pounds Coffee type B

m.ananth@hotmail.ca