SOLUTION: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 572980: how many liters of a 80% acid solution must be mixed with a 10% acid solution to get 560liters of a 70% acid solution
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
percent ---------------- quantity
Acid solution Type I 80.00% ---------------- x L
Acid solution type II 10.00% ------ 560 - x L
Mixture 70.00% ---------------- 560

80.00%x+10.00%(560-x)=70.00%*560
80x+10(560-x)= 39200
80x+5600-10x=39200
80x-10x =39200 -5600
70x= 33600
/70
x =480L 80.00% Acid solution Type I
80L 10.00% Acid solution type II