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| Question 57259:   Pam has some nickels, dimes, and quarters worth$6.75. There are four times as many nickels as dimes, and five more quarters than dimes. How many of each kind of coin does she have?
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! Translate each statement to simple equation:
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 "Pam has some nickels, dimes, and quarters worth $6.75."
 .05n + .10d + .25q = 6.75
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 "There are four times as many nickels as dimes,"
 n = 4d
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 "and five more quarters than dimes."
 q = d + 5
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 How many of each kind of coin does she have?
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 Take the 1st equation: Substitute: 4d for n, and (d+5) for q:
 .05(4d) + .10d + .25(d+5) = 6.75
 .2d + .1d + .25d + 1.25 = 6.75
 .55d = 6.75 - 1.25
 .55d = 5.50
 d = 5.50/.55
 d = 10 dimes
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 I'll let you find the number of nickels and quarters using the applicable equation. Check all 3 solutions in the 1st equation.
 
 
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