SOLUTION: 8/ (3+6i) in a+bi form

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: 8/ (3+6i) in a+bi form      Log On


   



Question 572314: 8/ (3+6i) in a+bi form
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
8/ (3+6i) in a+bi form
----
Multiply numeraor and denominator by 3-6i to get:
----
[8(3-6i)]/[(3+6i)(3-6i)]
-----
[24-48i]/(9+36)
------
=[24-48i]/45
----------
= (8/15) - (16/15)i
===========================
Cheers,
Stan H.
===========================