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| Question 572314:  8/ (3+6i) in a+bi form
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! 8/ (3+6i) in a+bi form ----
 Multiply numeraor and denominator by 3-6i to get:
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 [8(3-6i)]/[(3+6i)(3-6i)]
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 [24-48i]/(9+36)
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 =[24-48i]/45
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 = (8/15) - (16/15)i
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 Cheers,
 Stan H.
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