SOLUTION: The equation for the perpendicular line given that (6, -5) and 9x +8y=7.
Here is what I have done so far for the parallel line that I had to figure:
y=-9/8x+7/8
slope is -9/
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-> SOLUTION: The equation for the perpendicular line given that (6, -5) and 9x +8y=7.
Here is what I have done so far for the parallel line that I had to figure:
y=-9/8x+7/8
slope is -9/
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Question 572128: The equation for the perpendicular line given that (6, -5) and 9x +8y=7.
Here is what I have done so far for the parallel line that I had to figure:
y=-9/8x+7/8
slope is -9/8
y-(-5)=-9/8(x-6)
y=-9/8x +7/4
y=8/9x and now I am stuck. sigh. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The equation for the perpendicular line given that (6, -5) and 9x +8y=7.
Here is what I have done so far for the parallel line that I had to figure:
y=-9/8x+7/8
slope is -9/8
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Slope of a line perpendicular to the given line must be (8/9)
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Form: y = mx + b where m = 8/9 and y = -5 when x = 6
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-5 = (8/9)6 + b
-45/9 = 48/9 + b
b = -93/9 = -31/3
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Equation:
y = (8/9)x -(31/3)
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Cheers,
Stan H.
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