SOLUTION: A 2 digit number exceeds twice the sum of its digits by 9, that number when reversed gives 8 times the sum of its digits. Find the number

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Question 571992: A 2 digit number exceeds twice the sum of its digits by 9, that number when reversed gives 8 times the sum of its digits. Find the number
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 10's digit = +a+
Let the 1's digit = +b+
The number is +10a+%2B+b+
The number reversed is +10b+%2B+a+
--------------------------------
given:
(1) +10a+%2B+b+=+2%2A%28+a+%2B+b+%29+%2B+9+
(2) +10b+%2B+a+=+8%2A%28+a+%2B+b+%29+
--------------------------------------
(1) +10a+%2B+b+=+2a+%2B+2b+%2B+9+
(1) +10a+-+2a+%2B+b+-+2b+=+9+
(1) +8a+-+b+=+9+
and
(2) +10b+%2B+a+=+8%2A%28+a+%2B+b+%29+
(2) +10b+%2B+a+=+8a+%2B+8b+
(2) +7a+=+2b+
(2) +a+=+%282%2F7%29%2Ab+
Substitute this into (1)
(1) +8a+-+b+=+9+
(1) +8%2A%282%2F7%29%2Ab+-+b+=+9+
(1) +16b+-+7b+=+63+
(1) +9b+=+63+
(1) +b+=+7+
and, since
(2) +a+=+%282%2F7%29%2Ab+
(2) +a+=+%282%2F7%29%2A7+
(2) +a+=+2+
The number is 27
check:
+27+=+2%2A%28+2+%2B+7+%29+%2B+9+
+27+=+18+%2B+9+
+27+=+27+
and
+72+=+8%2A%28+2+%2B+7+%29+
+72+=+72+
OK