SOLUTION: $4,200 is invested , part of it at 5% and part at 6%. The total yield at simple interest for one year is 232. How much was invested at each rate?
I figure it is a D=RT problem b
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: $4,200 is invested , part of it at 5% and part at 6%. The total yield at simple interest for one year is 232. How much was invested at each rate?
I figure it is a D=RT problem b
Log On
Question 571962: $4,200 is invested , part of it at 5% and part at 6%. The total yield at simple interest for one year is 232. How much was invested at each rate?
I figure it is a D=RT problem but I'm not sure how to set it up. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! $4,200 is invested , part of it at 5% and part at 6%.
The total yield at simple interest for one year is 232.
How much was invested at each rate?
:
Here is how to set it up
:
Let x = amt invested at 6%
total was given as $4200, therefore:
(4200-x) = amt invested at 5%
:
.06x + .05(4200-x) = 232
