SOLUTION: . What is the largest natural number by which the product of three consecutive even natural numbers is Always divisible?

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Question 571610: . What is the largest natural number by which the product of three consecutive even natural numbers is Always divisible?

Answer by KMST(5328) About Me  (Show Source):
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The smallest three consecutive even natural numbers are 2,4,and 6, and their product is 48, so the answer could be 48 or less, but cannot be more than 48 because that would not work for 2, 4, and 6.
For a general case, three consecutive even natural numbers can be represented as
2n 2%28n%2B1%29 and 2%28n%2B2%29
Their product would be
2n%2A%282%28n%2B1%29%29%2A%282%28n%2B2%29%29=8n%28n%2B1%29%28n%2B2%29
It is obviously divisible by 8, but there are factors in
n n%2B1 and n%2B2 that we have to take into account.
At least one of those three numbers is even (maybe just n%2B1), so there is and factor 2 in n%28n%2B1%29%28n%2B2%29.
At least one of n n%2B1 and n%2B2 is divisible by 3, so there is and extra factor 3 in n%28n%2B1%29%28n%2B2%29.
We have the factors 8, 2, and 3, so the product of any three consecutive even natural numbers is always divisible by
8%2A2%2A3=48