SOLUTION: For a polynomial f(x) with real coefficients having given the degree and zeros. Degree 4; zeros:-2-5i; 5 multiplicity 2

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Question 571036: For a polynomial f(x) with real coefficients having given the degree and zeros.
Degree 4; zeros:-2-5i; 5 multiplicity 2

Answer by reviewermath(1029) About Me  (Show Source):
You can put this solution on YOUR website!
The conjugate of -2-5i is -2+5i. We first get a quadratic equation having -2-5i and -2+5i as roots.
sum = (-2-5i) + (-2+5i) = -4
product = (-2-5i)(-2+5i) = 29
x%5E2-+%28sum%29x+%2B+product+=+0
The quadratic equation is x%5E2+%2B+4x+%2B+29+=+0
Next, we get the quadratic equation having 5 as a double root.
The quadratic equation is %28x-5%29%5E2+=+0
We multiply the two quadratic equations to get the polynomial of degree 4.
%28x%5E2+%2B+4x+%2B+29%29%2A%28x-5%29%5E2+=+0
x%5E4+-6x%5E3+%2B14x%5E2+-190x+%2B+725+=+0
Answer: x%5E4+-6x%5E3+%2B14x%5E2+-190x+%2B+725+=+0