Question 57050: 6. find the slope, if it exists, of the line
(-6,6)(-4,5)(-2,4)(0,3)(2,2)(4,1)(6,0)
15. Graph the line containing the given pair of points and find the slope.
(5,3),(-3,-4)
25. find the slope or rate of change.
Slope of long's peak. From a base elevation of 9600 ft, Long's peak in colorado rises to a summit elevation of 14,255 ft over a horizontal distance of 15,840 ft. Find the grade of long's peak.
50. find slope, if exists.
16 + 2x - 8y = 0
Answer by BGluvsmath(64)   (Show Source):
You can put this solution on YOUR website! 6. Taking into account just the intercepts to graph this line (though the slope is found the same way regardless of which two points you choose):
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, 3) and (x2, y2) = (6, 0).
Slope a is  .
Intercept is found from equation  , or  . From that,
intercept b is  , or  .
y=(-0.5)x + (3)
Your graph:
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15.
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (5, 3) and (x2, y2) = (-3, -4).
Slope a is  .
Intercept is found from equation , or  . From that,
intercept b is , or  .
y=(0.875)x + (-1.375)
Your graph:
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25. Forget the graph on this one. Also note...4655 is the distance between base elevation and summit elevation.
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, 4655) and (x2, y2) = (15840, 0).
Slope a is  .
Intercept is found from equation , or  . From that,
intercept b is , or  .
y=(-0.293876262626263)x + (4655)
Your graph:
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50. 16 + 2x - 8y = 0 in slope-intercept form:
-8y=-2x-16
y=(1/4)x+2. The slope is 1/4 and here is the graph:
| Solved by pluggable solver: FIND a line by slope and one point |
What we know about the line whose equation we are trying to find out:
- it goes through point (0, 2)
- it has a slope of .25
First, let's draw a diagram of the coordinate system with point (0, 2) plotted with a little blue dot:
Write this down: the formula for the equation, given point  and intercept a, is
 (see a paragraph below explaining why this formula is correct)
Given that a=.25, and  , we have the equation of the line:
Explanation: Why did we use formula  ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point ( ,  ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ):  Here, we know a, , and , and do not know b. It is easy to find out: . So, then, the equation of the line is:  .
Here's the graph:
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(Although I already worked out the equation, I did this mainly for the graph.)
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