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Question 570227: I've been out sick since Monday and have been getting my work sent home. I've missed this lesson and can't for the life of me figure out how to do this. I've got 10 other similar problems to do but should be able to figure it out if some kind soul will help me understand.
Calculate the distance from point (-2,3) to the line y=x+1
I would really, really appreciate an explanation not just an answer since I have 9 more of these :)
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Calculate the distance from point (-2,3) to the line y=x+1
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The distance from a point to a line is the shortest distance, which is along the line perpendicular to the given line.
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The slope, m of y = x + 1 is 1.
The slope of lines perpendicular is the neg inverse, = -1
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Find the eqn of the line thru the point with a slope of -1.
y = mx + b
3 = -1*(-2) + b
b = 1
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The line perpendicular thru the point is
y = -x + 1
Find the intersection of the 2 lines.
y = x + 1
y =-x + 1
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2y = 2
y = 1
x = 0
The point (0,1) is the intersection.
Find the distance from (0,1) to (-2,3)
Answer by josmiceli(19441)  (Show Source):
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