SOLUTION: The stopping distance "d" (in feet) for a car traveling "v" mph when the driver has a reaction time of "t" is given by:
d = 1.5tv + 0.06v2
The reaction time of a driver is
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d = 1.5tv + 0.06v2
The reaction time of a driver is
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Question 570189: The stopping distance "d" (in feet) for a car traveling "v" mph when the driver has a reaction time of "t" is given by:
d = 1.5tv + 0.06v2
The reaction time of a driver is 0.5 sec. If the stopping distance is 187.5 ft, how fast is the car going (in mph)?
You can put this solution on YOUR website! I know the below is wrong... don't know what i'm doing wrong:
1.5(.5)v+.06v^2=187.5
.75v+.06v^2=187.5
.06v^2+.75v-187.5
multiply 10 with everything to get rid of decimals
0v^2+8v-1875
8v=1875
v=234
i know this must be wrong please help.
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