SOLUTION: 1. Find the equation of the parabola with vertex at (3,8) directrix Parabola 2. Find the equation of the parabola with vertex at (5,-1), focus (3,-1) With the way please

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 1. Find the equation of the parabola with vertex at (3,8) directrix Parabola 2. Find the equation of the parabola with vertex at (5,-1), focus (3,-1) With the way please       Log On


   



Question 570123: 1. Find the equation of the parabola with vertex at (3,8) directrix Parabola

2. Find the equation of the parabola with vertex at (5,-1), focus (3,-1)
With the way please

Answer by lwsshak3(11628) About Me  (Show Source):
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1. Find the equation of the parabola with vertex at (3,8) directrix Parabola
(insufficient information to solve)
2. Find the equation of the parabola with vertex at (5,-1), focus (3,-1)
With the way please
Standard form of equation of parabola with given data: (y-k)^2=-4p(x-h), with (h,k) being the (x,y) coordinates of the vertex. Given parabola opens leftward with axis of symmetry, y=-1.
p=distance from the vertex to focus on the axis of symmetry=2
4p=8
Equation of given parabola: (y+1)^2=-8(x-5)