SOLUTION: A right triangle has one vertex on the graph of {{{y=x^3}}}, x>0 at (x,y), another at the origin, and the third on the positive y-axis at (0,y). Express the area A of the triangle

Algebra ->  Surface-area -> SOLUTION: A right triangle has one vertex on the graph of {{{y=x^3}}}, x>0 at (x,y), another at the origin, and the third on the positive y-axis at (0,y). Express the area A of the triangle       Log On


   



Question 570043: A right triangle has one vertex on the graph of y=x%5E3, x>0 at (x,y), another at the origin, and the third on the positive y-axis at (0,y). Express the area A of the triangle as a function of x.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A right triangle has one vertex on the graph of y=x%5E3, x>0 at (x,y), another at the origin, and the third on the positive y-axis at (0,y). Express the area A of the triangle as a function of x.
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Area+=+b%2Ah%2F2+=+x%2Ax%5E3%2F2
= x%5E4%2F2