SOLUTION: Can you please help me on the following problem: A rectangle whose perimeter is 144 is 9 feet longer than it is wide. I have to find the dimensions and area, can you please help me

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Question 56987: Can you please help me on the following problem: A rectangle whose perimeter is 144 is 9 feet longer than it is wide. I have to find the dimensions and area, can you please help me.
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangle whose perimeter is 144 is 9 feet longer than it is wide. I have to find the dimensions and area.
The formula for the perimeter of a rectangle is:highlight%28P=2L%2B2W%29, where P=perimeter, L=length, and W=width. We can find the dimensions of the rectangle with this.
P=144
W=x
L=x+9 (9 feet longer)
Plug them into your formula:
144=2%28x%2B9%29%2B2x
144=2x%2B18%2B2x
144=4x%2B18
144-18=4x%2B18-18
126=4x
126%2F4=4x%2F4
31.5=x
Width (W): x=31.5 ft
Length (L): x+9=31.5+9=40.5 ft
The Formula for the area of a rectangle is: highlight%28A=WL%29
A=%2831.5%29%2840.5%29
highlight%28A=1275.75ft%5E2%29
Happy Calculating!!!