SOLUTION: At a circus, 135 clowns are getting into cars. Blue cars hold 20 clowns and red cars only hold 15. How many of each are there?

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: At a circus, 135 clowns are getting into cars. Blue cars hold 20 clowns and red cars only hold 15. How many of each are there?       Log On


   

Question 569855: At a circus, 135 clowns are getting into cars. Blue cars hold 20 clowns and red cars only hold 15. How many of each are there?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
At a circus, 135 clowns are getting into cars. Blue cars hold 20 clowns and red cars only hold 15. How many of each are there?
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20b + 15r = 135
20b = 135-15r
4b = 27 - 3r
b = (27-3r)/4
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b = (3/4)(9-r)
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Graph and look for whole number solutions.
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b = 6 when r = 1
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Answers:
6 blue cars and 1 red car
OR
3 blue cars and 5 red cars
Or
0 blue cars and 9 red cars
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Cheers,
Stan H.