Question 569139: Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him. After 1.2 hours, Kayla finally caught up. Find Jose's average speed.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Kayla left 2.1 hours later traveling 35 mph faster in an effort to catch up to him.
After 1.2 hours, Kayla finally caught up. Find Jose's average speed.
:
From the information given:
1.2 hrs is K's travel time (sorry about that)
and
2.1 + 1.2 = 3.3 hrs is J's travel time
:
When K catches, J, they will have traveled the same distance.
Let j = J's speed
then
(j+35) = K's speed
:
Write a distance equation: Dist = speed * time
:
3.3j = 1.2(j+35)
3.3j = 1.2j + 42
3.3j - 1.2j = 42
2.1j = 42
j = 42/2.1
j = 20 mph is J's average speed
:
:
Check this by finding the distance each traveled, they should be equal
3.3(20) = 66 mi
1.2(55) = 66 mi
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