SOLUTION: How would you find the missing numbers in the slopes (x) and (y) and it's (m) ? 1. ( n , 11/2 ) ( - 1/4 , 0 ) m = -22 2. ( 4 , n ) ( 1 , a-b) m = 2b/3

Algebra ->  Linear-equations -> SOLUTION: How would you find the missing numbers in the slopes (x) and (y) and it's (m) ? 1. ( n , 11/2 ) ( - 1/4 , 0 ) m = -22 2. ( 4 , n ) ( 1 , a-b) m = 2b/3      Log On


   

Question 568948: How would you find the missing numbers in the slopes (x) and (y) and it's (m) ?
1. ( n , 11/2 ) ( - 1/4 , 0 )
m = -22
2. ( 4 , n ) ( 1 , a-b)
m = 2b/3
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The letter m is often used for slope of a line, and that’s what I bet the M in your problem stands for.
The slope of the line connecting ( n , 11/2 ) and ( - 1/4 , 0 ) is the difference in y-coordinates divided by the difference in their x-coordinates:
Slope=m=
-22=22%2F%284n%2B1%29 --> 4n%2B1=22%2F%28-22%29 --> 4n%2B1=-1 --> 4n=-2 --> n=-1%2F2
The slope of the line connecting ( 4 , n ) and ( 1 , a-b) is
Slope=%28n-%28a-b%29%29%2F%284-1%29=%28n-a%2Bb%29%2F3
%28n-a%2Bb%29%2F3=2b%2F3 --> n-a%2Bb=2b --> n=a-b