SOLUTION: a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. whats the probability that you have one candy of each favor.
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-> SOLUTION: a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. whats the probability that you have one candy of each favor.
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Question 568857: a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. whats the probability that you have one candy of each favor. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a bag contains 6 cherry, 3 orange, and 2 lemon candies. you reach in and take 3 pieces of candy at random. whats the probability that you have one candy of each favor.
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# of ways to succeed: 6*3*2 = 36
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# of random draws of three: 11C3 = 165
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P(one of each flavor) = 36/165
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Cheers,
Stan H.