SOLUTION: Find two consecutive even integers such that the sum of the larger and twice the smaller is 62.

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Question 56840: Find two consecutive even integers such that the sum of the larger and twice the smaller is 62.
Answer by mszlmb(115) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive even integers such that the sum of the larger and twice the smaller is 62.
x is smaller y is larger:
They are consecutive AND EVEN, so x+2=y
Large+2Small=62, or
Y+2X=62. We know y=x+2, so let's substitute x+2 for y
(x+2)+2x=62 simplify
x+2+2x=62 minus 2 both sides
3x=60 divide by 3
x=20
The smaller number is 20, so the larger is [20+2] 22.
The numbers are 20 and 22
Let's check:
They are consecutive even integers
and 22+2(20)=62 so there we go!