SOLUTION: y= (x+4)-(x+1)
the (brackets) are supposed to be the absolute value bar lines
i understand how to get a resulting graph by graphing both vectors and adding the y values from left
Algebra ->
Absolute-value
-> SOLUTION: y= (x+4)-(x+1)
the (brackets) are supposed to be the absolute value bar lines
i understand how to get a resulting graph by graphing both vectors and adding the y values from left
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Question 568353: y= (x+4)-(x+1)
the (brackets) are supposed to be the absolute value bar lines
i understand how to get a resulting graph by graphing both vectors and adding the y values from left to right and then plotting the points.
my question is what is the resulting graph supposed to tell you?
i'm confused because i don't really get how to read the graph
i have worked out that the resulting graph looks like a rigid S shape from using an algebraic method
for x<-2
y= -(x+2) +(x+1)
= -x-2+x+1
y=-1
for -2
y=x+2+x+1
y=2x+3
for x>-1
y=x+2-x-1
y=1
if i graph these 3 equations, i will get the same resulting graph.
does it mean the points on the resulting graph are the solutions?
thanks in advance. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! y= |x+2|-|x+1|
--------------------
for x<-2
y= -(x+2) +(x+1)
= -x-2+x-1
-----------------------
for -2
y=x+2+x+1
y=2x+3
------------------------
for x >-1
y=x+2-x-1
y=1
---------------------------
if i graph these 3 equations, i will get the same resulting graph.
does it mean the points on the resulting graph are the solutions?
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Ans: Yes
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Cheers,
Stan H.
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