SOLUTION: identify the conic represented by x^2-4y-6x+9=0

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Question 568252: identify the conic represented by x^2-4y-6x+9=0
Answer by lwsshak3(11628) About Me  (Show Source):
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identify the conic represented by x^2-4y-6x+9=0
complete the square
(x^2-6x+9)-4y+9-9=0
4y=(x-3)^2
y=(1/4)(x-3)^2
This is an equation for a parabola with vertex at (3,0)
Parabola opens upwards with minimum=0.
Standard form of equation for given parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the slope or steepness of the curve.